Python Pandas - 如何以毫秒频率对 DateTimeIndex 执行 ceil 操作

要以毫秒频率对DateTimeIndex执行ceil操作，请使用该方法。对于毫秒频率，使用值为“ms”的freq参数。DateTimeIndex.ceil()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为5，频率为S，即秒。时区是澳大利亚/阿德莱德-

datetimeindex = pd.date_range(2021-10-18 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=40S)

以毫秒为频率对DateTimeIndex日期进行Ceil操作。对于毫秒频率，我们使用了ms-

print("\nPerforming ceil operation with milliseconds frequency...\n", datetimeindex.ceil(freq=ms))

示例

以下是代码-

import pandas as pd #DatetimeIndexwithperiod5andfrequencyasSi.e.seconds #timezoneisAustralia/Adelaide datetimeindex = pd.date_range(2021-10-18 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=40S) #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #CeiloperationonDateTimeIndexdatewithmillisecondsfrequency # For milliseconds frequency, we have used ms print("\nPerforming ceil operation with milliseconds frequency...\n", datetimeindex.ceil(freq=ms))输出结果

这将产生以下代码-

DateTimeIndex... DatetimeIndex([2021-10-18 07:20:32.261811624+10:30, 2021-10-18 07:21:12.261811624+10:30, 2021-10-18 07:21:52.261811624+10:30, 2021-10-18 07:22:32.261811624+10:30, 2021-10-18 07:23:12.261811624+10:30], dtype=datetime64[ns, Australia/Adelaide], freq=40S) DateTimeIndex frequency... <40 * Seconds> Performing ceil operation with milliseconds frequency... DatetimeIndex([2021-10-18 07:20:32.262000+10:30, 2021-10-18 07:21:12.262000+10:30, 2021-10-18 07:21:52.262000+10:30, 2021-10-18 07:22:32.262000+10:30, 2021-10-18 07:23:12.262000+10:30], dtype=datetime64[ns, Australia/Adelaide], freq=None)