逐元素检查 IntervalIndex 中的 Intervals 是否包含 Python Pandas 中的值

要返回与当前相同但在指定一侧关闭的IntervalArray，请使用set_closed()参数设置为both的方法。

首先，导入所需的库-

import pandas as pd

创建IntervalArray-

index = pd.arrays.IntervalArray.from_breaks(range(6))

显示间隔-

print("IntervalIndex...\n",index)

返回一个与当前相同但在指定侧关闭的IntervalArray，即这里的“两者”-

print("\nResult...",index.set_closed(both))

示例

以下是代码-

import pandas as pd #创建间隔数组 index = pd.arrays.IntervalArray.from_breaks(range(6)) #显示间隔 print("IntervalIndex...\n",index) #显示间隔 length print("\nIntervalIndex length...\n",index.length) #左边界 print("\nThe left bound for the IntervalIndex...\n",index.left) #正确的界限 print("\nThe right bound for the IntervalIndex...\n",index.right) #返回一个与当前相同但在指定时间关闭的IntervalArray # side i.e. "both" here print("\nResult...",index.set_closed(both))输出结果

这将产生以下输出-

IntervalIndex... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]] Length: 5, dtype: interval[int64, right] IntervalIndex length... Int64Index([1, 1, 1, 1, 1], dtype=int64) The left bound for the IntervalIndex... Int64Index([0, 1, 2, 3, 4], dtype=int64) The right bound for the IntervalIndex... Int64Index([1, 2, 3, 4, 5], dtype=int64) Result... <IntervalArray> [[0, 1], [1, 2], [2, 3], [3, 4], [4, 5]] Length: 5, dtype: interval[int64, both]