Python Pandas - 如何以每小时的频率对 DateTimeIndex 执行 ceil 操作

要以每小时的频率对DateTimeIndex执行ceil操作，请使用方法。对于每小时频率，使用值为“H”的freq参数。DateTimeIndex.ceil()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为5，频率为分钟，即分钟-

datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=20min)

以每小时的频率对DateTimeIndex日期执行Ceil操作。对于每小时频率，我们使用了“H”-

print("\nPerforming ceil operation with hourly frequency...\n", datetimeindex.ceil(freq=H))

示例

以下是代码-

import pandas as pd #DatetimeIndexwithperiod5andfrequencyasmini.e.minutes #timezoneisAustralia/Adelaide datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=20min) #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #CeiloperationonDateTimeIndexdatewithhourlyfrequency # For hourly frequency, we have used H print("\nPerforming ceil operation with hourly frequency...\n", datetimeindex.ceil(freq=H))输出结果

这将产生以下代码-

DateTimeIndex... DatetimeIndex([2021-09-29 07:20:32.261811624+09:30, 2021-09-29 07:40:32.261811624+09:30, 2021-09-29 08:00:32.261811624+09:30, 2021-09-29 08:20:32.261811624+09:30, 2021-09-29 08:40:32.261811624+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=20T) DateTimeIndex frequency... <20 * Minutes> Performing ceil operation with hourly frequency... DatetimeIndex([2021-09-29 08:00:00+09:30, 2021-09-29 08:00:00+09:30, 2021-09-29 09:00:00+09:30, 2021-09-29 09:00:00+09:30, 2021-09-29 09:00:00+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=None)