Python Pandas - 创建一个以 MultiIndex 的级别作为列的 DataFrame，但避免设置返回的 DataFrame 的索引

要创建以MultiIndex的级别作为列的DataFrame，请使用.该指标参数设置假以避免将返回数据框的索引multiIndex.to_frame()

首先，导入所需的库-

import pandas as pd

MultiIndex是Pandas对象的多级或分层索引对象。创建数组-

arrays = [[1, 2, 3, 4], [John, Tim, Jacob, Chris]]

“names”参数设置每个索引级别的名称。将from_arrays()被用来创建一个多指标-

multiIndex = pd.MultiIndex.from_arrays(arrays, names=(ranks, student))

使用to_frame().使用“index”参数并将其设置为“False”以避免设置返回的DataFrame的索引-

dataFrame = multiIndex.to_frame(index=False)

示例

以下是代码-

import pandas as pd #MultiIndexisamulti-level,orhierarchical,indexobjectforpandasobjects #Createarrays arrays = [[1, 2, 3, 4], [John, Tim, Jacob, Chris]] # The "names" parameter sets the names for each of the index levels #Thefrom_arrays()isusedtocreateaMultiIndex multiIndex = pd.MultiIndex.from_arrays(arrays, names=(ranks, student)) #displaytheMultiIndex print("The Multi-index...\n",multiIndex) #getthelevelsinMultiIndex print("\nThe levels in Multi-index...\n",multiIndex.levels) #CreateaDataFramewiththelevelsoftheMultiIndexascolumnsusingto_frame() # Use the "index" 参数并将其设置为 "False" to avoid setting the index of the returned #DataFrame dataFrame = multiIndex.to_frame(index=False) #ReturntheDataFrame print("\nThe DataFrame...\n",dataFrame)输出结果

这将产生以下输出-

The Multi-index... MultiIndex([(1, John), (2, Tim), (3, Jacob), (4, Chris)], names=[ranks, student]) The levels in Multi-index... [[1, 2, 3, 4], [Chris, Jacob, John, Tim]] The DataFrame... ranks student 0 1 John 1 2 Tim 2 3 Jacob 3 4 Chris