MongoDB查询要跳过n个第一个文件？

要跳过特定数量的文档，请使用skip()和limit。让我们创建一个包含文档的集合-

> db.demo246.insertOne({"StudentFirstName":"Chris","StudentLastName":"Brown"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0d71627c0c63e7dba65") } > db.demo246.insertOne({"StudentFirstName":"John","StudentLastName":"Doe"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0e21627c0c63e7dba66") } > db.demo246.insertOne({"StudentFirstName":"John","StudentLastName":"Smith"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0ea1627c0c63e7dba67") } > db.demo246.insertOne({"StudentFirstName":"Carol","StudentLastName":"Taylor"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0f91627c0c63e7dba68") }

在find()方法的帮助下显示集合中的所有文档-

> db.demo246.find();

这将产生以下输出-

{ "_id" : ObjectId("5e46b0d71627c0c63e7dba65"), "StudentFirstName" : "Chris", "StudentLastName" : "Brown" } { "_id" : ObjectId("5e46b0e21627c0c63e7dba66"), "StudentFirstName" : "John", "StudentLastName" : "Doe" } { "_id" : ObjectId("5e46b0ea1627c0c63e7dba67"), "StudentFirstName" : "John", "StudentLastName" : "Smith" } { "_id" : ObjectId("5e46b0f91627c0c63e7dba68"), "StudentFirstName" : "Carol", "StudentLastName" : "Taylor" }

以下是MongoDB中的查询以跳过n个第一文档-

> db.demo246.find().skip(2).limit(1);

这将产生以下输出-

{ "_id" : ObjectId("5e46b0ea1627c0c63e7dba67"), "StudentFirstName" : "John", "StudentLastName" : "Smith" }