Python程序在列表中查找第二大数字

在本文中，我们将学习下面给出的问题陈述的解决方案。

问题陈述 -我们得到一个列表，我们需要在列表中显示第二大数字。

有三种解决问题的方法-

方法1：我们使用set()函数和remove()函数

示例

list1 = [11,22,1,2,5,67,21,32] # to get unique elements new_list = set(list1) # removing the largest element from list1 new_list.remove(max(new_list)) # now computing the max element by built-in method? print(max(new_list))

输出结果

32

方法2：我们使用sort()方法和负索引

示例

list1 = [11,22,1,2,5,67,21,32] # using built-in sort method list1.sort() # second last element print("Second largest element in the list is:", list1[-2])

输出结果

Second largest element in the list is: 32

方法3：我们使用蛮力法获得第二个最大元素

示例

list1 = [11,22,1,2,5,67,21,32] #assuming max_ is equal to maximum of element at 0th and 1st index and secondmax is the minimum among them max_=max(list1[0],list1[1]) secondmax=min(list1[0],list1[1]) for i in range(2,len(list1)): # if found element is greater than max_ if list1[i]>max_: secondmax=max_ max_=list1[i] #if found element is greator than secondmax else: if list1[i]>secondmax: secondmax=list1[i] print("Second highest number is the list is : ",str(secondmax))

输出结果

Second highest number is the list is : 32

结论

在本文中，我们了解了如何在列表中找到第二大元素。