可以在AP中随机选择三个数字的C ++程序概率

给定一个带有数字“n”的数组，任务是找到三个随机选择的数字出现在AP中的概率。

示例

Input-: arr[] = { 2,3,4,7,1,2,3 } Output-: Probability of three random numbers being in A.P is: 0.107692 Input-:arr[] = { 1, 2, 3, 4, 5 } Output-: Probability of three random numbers being in A.P is: 0.151515

以下程序中使用的方法如下-

输入正整数数组

计算数组的大小

应用下面给出的公式找出三个随机数出现在AP中的概率

3n/（4（n*n）–1）

打印结果

算法

Start Step 1-> function to calculate the probability of three random numbers be in AP double probab(int n) return (3.0 * n) / (4.0 * (n * n) - 1) Step 2->In main() declare an array of elements as int arr[] = { 2,3,4,7,1,2,3 } calculate size of an array as int size = sizeof(arr)/sizeof(arr[0]) call the function to calculate probability as probab(size) Stop

示例

#include <bits/stdc++.h> using namespace std; //calculate probability of three random numbers be in AP double probab(int n) { return (3.0 * n) / (4.0 * (n * n) - 1); } int main() { int arr[] = { 2,3,4,7,1,2,3 }; int size = sizeof(arr)/sizeof(arr[0]); cout<<"probability of three random numbers being in A.P is : "<<probab(size); return 0; }

输出结果

Probability of three random numbers being in A.P is: 0.107692