C#中的BitConverter.Int64BitsToDouble()方法

C#中的BitConverter.Int64BitsToDouble()方法用于将指定的64位带符号整数重新解释为双精度浮点数。

语法

以下是语法-

public static double Int64BitsToDouble (long val);

上面的参数值是要转换的数字。

示例

现在让我们看一个实现BitConverter.Int64BitsToDouble()方法的示例-

using System; public class Demo { public static void Main(){ long d = 9846587687; Console.Write("Value (64-bit signed integer) = "+d); double res = BitConverter.Int64BitsToDouble(d); Console.Write("\nValue (double-precision floating point number) = "+res); } }

输出结果

这将产生以下输出-

Value (64-bit signed integer) = 9846587687 Value (double-precision floating point number) = 4.86486070491012E-314

示例

让我们看另一个例子-

using System; public class Demo { public static void Main(){ long d = 20; Console.Write("Value (64-bit signed integer) = "+d); double res = BitConverter.Int64BitsToDouble(d); Console.Write("\nValue (double-precision floating point number) = "+res); } }

输出结果

这将产生以下输出-

Value (64-bit signed integer) = 20 Value (double-precision floating point number) = 9.88131291682493E-323