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Python Pandas - 以毫秒频率对 TimeDeltaIndex 执行地板操作

2026-06-03 1 花语

要以毫秒频率对TimeDeltaIndex执行地板操作,请使用方法。对于毫秒频率,使用值为msfreq参数。TimeDeltaIndex.floor()

首先,导入所需的库-

import pandas as pd

创建一个TimeDeltaIndex对象。我们已经使用data参数设置了类似timedelta的数据-

tdIndex = pd.TimedeltaIndex(data =[5 day 8h 20min 35us 45ns, +17:42:19.999999, 7 day 3h 08:16:02.000055, +22:35:25.999999])

显示TimedeltaIndex-

print("TimedeltaIndex...\n", tdIndex)

以毫秒为频率对TimeDeltaIndex日期进行地板操作。对于毫秒频率,我们使用了ms-

print("\nPerforming Floor oper

示例

以下是代码-

import pandas as pd #CreateaTimeDeltaIndexobject # We have set the timedelta-like data using the data parameter tdIndex = pd.TimedeltaIndex(data =[5 day 8h 20min 35us 45ns, +17:42:19.999999, 7 day 3h 08:16:02.000055, +22:35:25.999999]) #displayTimedeltaIndex print("TimedeltaIndex...\n", tdIndex) #ReturnadataframeofthecomponentsofTimeDeltas print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components) #FlooroperationonTimeDeltaIndexdatewithmillisecondsfrequency # For milliseconds frequency, we have used ms print("\nPerforming Floor operation with milliseconds frequency...\n", tdIndex.floor(freq=ms))输出结果

这将产生以下代码-

TimedeltaIndex... TimedeltaIndex([5 days 08:20:00.000035045, 0 days 17:42:19.999999, 7 days 11:16:02.000055, 0 days 22:35:25.999999], dtype=timedelta64[ns], freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 5 8 20 0 0 35 45 1 0 17 42 19 999 999 0 2 7 11 16 2 0 55 0 3 0 22 35 25 999 999 0 Performing Floor operation with milliseconds frequency... TimedeltaIndex([ 5 days 08:20:00, 0 days 17:42:19.999000, 7 days 11:16:02, 0 days 22:35:25.999000], dtype=timedelta64[ns], freq=None)