要返回MultiIndex中请求级别的标签值向量,请使用该方法。将级别名称设置为参数。multiIndex.get_level_values()
首先,导入所需的库-
import pandas as pdMultiIndex是Pandas对象的多级或分层索引对象-
multiIndex = pd.MultiIndex.from_arrays([list(pqrrss), list(strvwx)],names=[One, Two])显示多索引-
print("The MultiIndex...\n",multiIndex)获取MultiIndex中的级别-
print("\nThe levels in MultiIndex...\n",multiIndex.levels)获取级别0的级别值-
print("\nLevel values...\n",multiIndex.get_level_values(0))以下是代码-
import pandas as pd #MultiIndexisamulti-level,orhierarchical,indexobjectforpandasobjects multiIndex = pd.MultiIndex.from_arrays([list(pqrrss), list(strvwx)],names=[One, Two]) #displaytheMultiIndex print("The MultiIndex...\n",multiIndex) #getthelevelsinMultiIndex print("\nThe levels in MultiIndex...\n",multiIndex.levels) #getlevelvaluesatlevel0 print("\nLevel values...\n",multiIndex.get_level_values(0)) # get level values with level name "Two" print("\nLevel values...\n",multiIndex.get_level_values("Two"))输出结果这将产生以下输出-
The MultiIndex... MultiIndex([(p, s), (q, t), (r, r), (r, v), (s, w), (s, x)], names=[One, Two]) The levels in MultiIndex... [[p, q, r, s], [r, s, t, v, w, x]] Level values... Index([p, q, r, r, s, s], dtype=object, name=One) Level values... Index([s, t, r, v, w, x], dtype=object, name=Two)