Python Pandas - 如何以秒频率舍入 DateTimeIndex

要以秒频率舍入DateTimeIndex，请使用方法。对于秒频率，使用值为S的freq参数。DateTimeIndex.round()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为5，频率为s即秒-

datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=28s)

以秒频率对DateTimeIndex日期进行舍入操作。对于秒频率，我们使用了“S”-

print("\nPerforming round operation with seconds frequency...\n", datetimeindex.round(freq=S))

示例

以下是代码-

import pandas as pd #DatetimeIndexwithperiod5andfrequencyassi.e.seconds #timezoneisAustralia/Adelaide datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=28s) #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #gettingthesecond res = datetimeindex.second #displayonlythesecond print("\nThe second from DateTimeIndex...\n", res) #RoundoperationonDateTimeIndexdatewithsecondsfrequency # For seconds frequency, we have used S print("\nPerforming round operation with seconds frequency...\n", datetimeindex.round(freq=S))输出结果

这将产生以下代码-

DateTimeIndex... DatetimeIndex([2021-09-29 07:20:32.261811624+09:30, 2021-09-29 07:21:00.261811624+09:30, 2021-09-29 07:21:28.261811624+09:30, 2021-09-29 07:21:56.261811624+09:30, 2021-09-29 07:22:24.261811624+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=28S) DateTimeIndex frequency... <28 * Seconds> The second from DateTimeIndex... Int64Index([32, 0, 28, 56, 24], dtype=int64) Performing round operation with seconds frequency... DatetimeIndex([2021-09-29 07:20:32+09:30, 2021-09-29 07:21:00+09:30, 2021-09-29 07:21:28+09:30, 2021-09-29 07:21:56+09:30, 2021-09-29 07:22:24+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=None)