Python Pandas - 以单个单位的倍数为频率舍入 DateTimeIndex

要将DateTimeIndex的频率舍入为单个单位的倍数，请使用方法。设置频率的freq参数。DateTimeIndex.round()

首先，导入所需的库-

import pandas as pd

DatetimeIndex周期为5，频率为H即小时-

datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=H)

显示日期时间索引-

print("DateTimeIndex...\n", datetimeindex)

以10分钟的频率舍入DateTimeIndex，即单个单位的倍数。对于分钟频率，我们使用了T-

print("\nPerforming round operation with multiples of a single unit frequency...\n", datetimeindex.round(freq=10T))

示例

以下是代码-

import pandas as pd #DatetimeIndexwithperiod5andfrequencyasHi.e.hours #timezoneisAustralia/Adelaide datetimeindex = pd.date_range(2021-09-29 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=H) #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #RoundaDateTimeIndexwith10minutesfrequencyi.e.multiplesofasingleunit # For minutes frequency, we have used T print("\nPerforming round operation with multiples of a single unit frequency...\n", datetimeindex.round(freq=10T))输出结果

这将产生以下代码-

DateTimeIndex... DatetimeIndex([2021-09-29 07:20:32.261811624+09:30, 2021-09-29 08:20:32.261811624+09:30, 2021-09-29 09:20:32.261811624+09:30, 2021-09-29 10:20:32.261811624+09:30, 2021-09-29 11:20:32.261811624+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=H) DateTimeIndex frequency... <Hour> Performing round operation with multiples of a single unit frequency... DatetimeIndex([2021-09-29 07:20:00+09:30, 2021-09-29 08:20:00+09:30, 2021-09-29 09:20:00+09:30, 2021-09-29 10:20:00+09:30, 2021-09-29 11:20:00+09:30], dtype=datetime64[ns, Australia/Adelaide], freq=None)