Python Pandas - 如何以每分钟的频率对 DateTimeIndex 执行地板操作

要以分钟频率对DateTimeIndex执行地板运算，请使用方法。对于每分钟频率，请使用值为T的freq参数。DateTimeIndex.floor()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为7，频率为s即秒-

datetimeindex = pd.date_range(2021-10-18 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=40S)

显示日期时间索引-

print("DateTimeIndex...\n", datetimeindex)

以分钟频率对DateTimeIndex日期进行地板操作。对于分钟频率，我们使用了“T”-

print("\nPerforming floor operation with minute frequency...\n", datetimeindex.floor(freq=T))

示例

以下是代码-

import pandas as pd #DatetimeIndexwithperiod7andfrequencyassi.e.seconds #timezoneisAustralia/Adelaide datetimeindex = pd.date_range(2021-10-18 07:20:32.261811624, periods=5, tz=Australia/Adelaide, freq=40S) #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #gettingtheminute res = datetimeindex.minute #displayonlytheminute print("\nThe minute from DateTimeIndex...\n", res) #FlooroperationonDateTimeIndexdatewithminutefrequency # For minute frequency, we have used T print("\nPerforming floor operation with minute frequency...\n", datetimeindex.floor(freq=T))输出结果

这将产生以下代码-

DateTimeIndex... DatetimeIndex([2021-10-18 07:20:32.261811624+10:30, 2021-10-18 07:21:12.261811624+10:30, 2021-10-18 07:21:52.261811624+10:30, 2021-10-18 07:22:32.261811624+10:30, 2021-10-18 07:23:12.261811624+10:30], dtype=datetime64[ns, Australia/Adelaide], freq=40S) DateTimeIndex frequency... <40 * Seconds> The minute from DateTimeIndex... Int64Index([20, 21, 21, 22, 23], dtype=int64) Performing floor operation with minute frequency... DatetimeIndex([2021-10-18 07:20:00+10:30, 2021-10-18 07:21:00+10:30, 2021-10-18 07:21:00+10:30, 2021-10-18 07:22:00+10:30, 2021-10-18 07:23:00+10:30], dtype=datetime64[ns, Australia/Adelaide], freq=None)