Python Pandas - 返回索引中最小值的 int 位置

要返回索引中最小值的int位置，请使用方法。index.argmin()

首先，导入所需的库-

import pandas as pd

创建索引-

index = pd.Index([15, 25, 55, 10, 100, 70, 35, 40, 55])

显示索引-

print("Pandas Index...\n",index)

获取索引中最小值的int位置-

print("\nGet the int position of the smallest value in the Index...\n",index.argmin())

示例

以下是代码-

import pandas as pd #创建索引 index = pd.Index([15, 25, 55, 10, 100, 70, 35, 40, 55]) #显示索引 print("Pandas Index...\n",index) #返回基础数据形状的元组 print("\nA tuple of the shape of underlying data...\n",index.shape) #返回索引中的元素数 print("\nNumber of elements in the index...\n",index.size) #Index中最小值的int位置 print("\nGet the int position of the smallest value in the Index...\n",index.argmin())输出结果

这将产生以下代码-

Pandas Index... Int64Index([15, 25, 55, 10, 100, 70, 35, 40, 55], dtype=int64) A tuple of the shape of underlying data... (9,) Number of elements in the index... 9 Get the int position of the smallest value in the Index... 3