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Python Pandas - 从类似数组的元组构造一个 IntervalArray 并返回每个 Interval 的左端点

2026-06-03 1 花语

要从类似数组的元组构造IntervalArray,请使用pandas.arrays。IntervalArray.from_tuples()方法。要返回IntervalArray中每个Interval的左端点,请使用array.left属性。

首先,导入所需的库-

import pandas as pd

从类似数组的元组构造一个新的IntervalArray-

array = pd.arrays.IntervalArray.from_tuples([(10, 25),(15, 70)])

显示间隔-

print("Our IntervalArray...\n",array)

获取左端点-

print("\nThe left endpoints of each Interval in the IntervalArray as an Index...\n", array.left)

示例

以下是代码-

import pandas as pd #从类似数组的元组构造一个新的IntervalArray array = pd.arrays.IntervalArray.from_tuples([(10, 25),(15, 70)]) #显示间隔数组 print("Our IntervalArray...\n",array) #获取IntervalArray的长度 #返回一个索引,其中的条目表示IntervalArray中每个Interval的长度 print("\nOur IntervalArray length...\n",array.length) #IntervalArray中每个Interval的中点作为索引 print("\nThe midpoint of each interval in the IntervalArray...\n",array.mid) #获取左端点 print("\nThe left endpoints of each Interval in the IntervalArray as an Index...\n",array.left)输出结果

这将产生以下代码-

Our IntervalArray... <IntervalArray> [(10, 25], (15, 70]] Length: 2, dtype: interval[int64, right] Our IntervalArray length... Int64Index([15, 55], dtype=int64) The midpoint of each interval in the IntervalArray... Float64Index([17.5, 42.5], dtype=float64) The left endpoints of each Interval in the IntervalArray as an Index... Int64Index([10, 15], dtype=int64)