Python Pandas - 返回一个包含按升序排序的 Index 对象中唯一值计数的系列

要返回包含按升序排序的Index对象的唯一值计数的系列，请使用参数升序为True的方法。index.value_counts()

首先，导入所需的库——

import pandas as pd

创建熊猫索引-

index = pd.Index([50, 10, 70, 110, 90, 50, 110, 90, 30])

显示熊猫指数-

print("Pandas Index...\n",index)

按升序排序的唯一值计数-

print("\nGet the count of unique values sorted in ascending order..." "\n",index.value_counts(ascending=True))

示例

以下是代码-

import pandas as pd #创建Pandas索引 index = pd.Index([50, 10, 70, 110, 90, 50, 110, 90, 30]) #显示Pandas索引 print("Pandas Index...\n",index) #返回索引中的元素数 print("\nNumber of elements in the index...\n",index.size) #返回数据的dtype print("\nThe dtype object...\n",index.dtype) #按升序排序的唯一值的计数 print("\nGet the count of unique values sorted in ascending order..." "\n",index.value_counts(ascending=True))输出结果

这将产生以下输出-

Pandas Index... Int64Index([50, 10, 70, 110, 90, 50, 110, 90, 30], dtype=int64) Number of elements in the index... 9 The dtype object... int64 Get the count of unique values sorted in ascending order... 10 1 70 1 30 1 50 2 110 2 90 2 dtype: int64