如何在R中剪切具有最小值的数据框列？

要切割具有最小值的数据框列，我们需要在min函数的帮助下使用cut函数指定最小值并将include.lowest参数设置为TRUE。我们还可以指定最大值，以便在切割列时也考虑最大值。

示例1

以下代码段创建了一个示例数据框-

x<-rpois(20,5) df1<-data.frame(x) df1

创建以下数据框-

x 1 6 2 7 3 4 4 3 5 6 6 2 7 7 8 2 9 3 10 2 11 5 12 4 13 3 14 8 15 11 16 2 17 6 18 3 19 3 20 4

要使用最小值和最大值切割x列，请将以下代码添加到上面的代码段中-

cut(df1$x,c(min(df1$x),3:10,max(df1$x)),include.lowest=TRUE)输出结果

如果您将上述所有给定的片段作为单个程序执行，它会生成以下输出-

[1] (5,6] (6,7] (3,4] [2,3] (5,6] [2,3] (6,7] [2,3] [2,3] [10] [2,3] (4,5] (3,4] [2,3] (7,8] (10,11] [2,3] (5,6] [2,3] [19] [2,3] (3,4] Levels: [2,3] (3,4] (4,5] (5,6] (6,7] (7,8] (8,9] (9,10] (10,11]

示例2

以下代码段创建了一个示例数据框-

y<-rpois(20,10) df2<-data.frame(y) df2

创建以下数据框-

y 1 16 2 10 3 11 4 5 5 12 6 10 7 8 8 6 9 11 10 3 11 13 12 12 13 10 14 11 15 8 16 9 17 7 18 8 19 8 20 9

要使用最小值和最大值切割y列，请将以下代码添加到上面的代码段中-

cut(df2$y,c(min(df2$y),4:15,max(df2$y)),include.lowest=TRUE)输出结果

如果您将上述所有给定的片段作为单个程序执行，它会生成以下输出-

[1] (15,16] (9,10] (10,11] (4,5] (11,12] (9,10] (7,8] (5,6] (10,11] [10] [3,4] (12,13] (11,12] (9,10] (10,11] (7,8] (8,9] (6,7] (7,8] [19] (7,8] (8,9] 13 Levels: [3,4] (4,5] (5,6] (6,7] (7,8] (8,9] (9,10] (10,11] ... (15,16]

示例3

以下代码段创建了一个示例数据框-

df3<-data.frame(z) df3

创建以下数据框-

z 1 3 2 2 3 1 4 2 5 1 6 6 7 2 8 2 9 2 10 1 11 0 12 1 13 1 14 1 15 2 16 1 17 3 18 0 19 4 20 2

要使用最小值和最大值切割列z，请将以下代码添加到上面的代码段中-

cut(df3$z,c(min(df3$z),1:5,max(df3$z)),include.lowest=TRUE)输出结果

如果您将上述所有给定的片段作为单个程序执行，它会生成以下输出-

[1] (2,3] (1,2] [0,1] (1,2] [0,1] (5,6] (1,2] (1,2] (1,2] [0,1] [0,1] [0,1] [13] [0,1] [0,1] (1,2] [0,1] (2,3] [0,1] (3,4] (1,2] Levels: [0,1] (1,2] (2,3] (3,4] (4,5] (5,6]